In the challenge is described that for a given p(x) in a certain step you get min(p(x))=8, max(p(x))=10 and middle(p(x))=8.5, even if the average avg(p(x))=9 I want you to use 8.5.<br>I understand how you get the average. But how can you calculate the middle?
did you see the post by harvestsnow in the other thread, i think this explains it pretty well;<br><br><div class="\"tbscode_standard_quote_headline\""><img alt="\"Quote\"" src="%5C">Quote from <a href="%5C">harvestsnow</a>:</div><div class="\"tbscode_standard_quote\"">The \"middle value\" is the value of the function at the middle of the interval.<br>For instance, the middle value of x^2 for the interval [0.00,0.01] is its value at 0.005, which is 0.000025.<br></div><br>